Solved Problems On Coefficient Of Friction An object of mass of 2kg is moving with a velocity of 12ms -2, the friction force acting on the body make the object stop at a distance of 22m. Using the above formula, we can find the coefficient of friction given velocity and distance. It is clear that the coefficient of friction arrived from both methods are the same. On rearranging the terms, we get the coefficient of friction as, Since in this case, we have considered the force acting on the object is friction force so that substituting the formula of the friction, we get the equation as We can take the magnitude of the equation as, The force acting on the object cannot have a negative value. Substituting in the above equation, we get Hence we can modify the equation asįrom Newton’s second law of motion, the relation between the acceleration and the force is given by, Here we consider the object is moving with a constant velocity so that the final velocity vf2 become zero.

V 0 2 is the initial velocity of the moving object.Ī is the acceleration, and d is the distance travelled by the object. Where, v f 2 is the final velocity of the moving object.

The kinematic equation of motion for given velocity and distance is, Now consider that initially the object is moving with velocity v 0, with the time its velocity changes and finally it is moving with velocity v f covering the distance d, then the coefficient of friction is given by Since the above two equations of friction are the same, we can equate them So that the friction is given by the equation, The normal reaction is equal to the net weight of the object given by F n=mg Where µ is the coefficient of friction and F n is the normal reaction. The friction force acting on the object is given by This work done is equal to the friction force times the distance, so we can write the equation as

Where m is the mass of the object and v is the velocity at which the object is moving. Since the object is moving, the stored potential energy is zero, and the energy loss is negligible during the process. The work done by the friction on the object is given by Method 1: considering the work done by the friction We can find the coefficient friction given velocity and distance by two methods. To find coefficient of friction given velocity and distance

Fsae tire coefficient of friction